#include <stdio.h>

/*
Exercise 2-4. Write an alternate version of squeeze (s 1,s2) that deletes
each character in s1 that matches any character in the string s2.
*/

/*
//squeeze: delete all c from s (needs below lines to work....)
void squeeze(char s[], char c)
{
int i, j;

for (i = j = 0; s[i] != '\0'; ++i)
	{
	if (s[i] != c)
		{
		s[j++] = s[i];
		}
	s[j] = '\0';
	}
}
//int i;
//strip null chars that are just there in the middle of the string... otherwise printf does not work
//for (i=0;i<5;++i)
//{
//if (input[i] == '\0'){input[i] = input[i+1]; input[i+1] = '\0'; }
//}

*/


//squeeze: Actual working reimplementation
void squeeze(char s[], char c)
{
int i,j;
for (i=0; s[i] != '\0'; ++i)
	{
	if (s[i] == c)//if s[i] is a charater to remove....
		{
		j=i;
		while(s[j] != '\0'){s[j++] = s[j+1];}//shift all characters above left, overwriting the character
		--i;//deincrement i, since the string was just shrunk by one and the one just above could indeed be a matching char
		}
	}
}

//squeezy: Delete all chars in s0 that match each single char in s1
void squeezy(char s0[], char s1[])
{
int i,j,z;
for (i=0; s0[i] != '\0'; ++i)
	{
	for (z=0; s1[z] != '\0'; ++z)
		{
		if (s0[i] == s1[z])//if s0[i] is a charater to remove....
			{
			j=i;
			while(s0[j] != '\0'){s0[j++] = s0[j+1];}//shift all characters above left, overwriting the character
			--i;//deincrement i, since the string was just shrunk by one and the one just above could indeed be a matching char
			}
		}
	}
}


int main(void)
{
//note: "char *" cannot be modified like; s[0] = 'a', char s[] needs to be used instead
char input[] = "Test input";

//squeeze(input,'e');
squeezy(input,"t");

printf("%s\n", input);


return 0;
}