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1 files changed, 80 insertions, 0 deletions

diff --git a/main.c b/main.c
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+++ b/main.c
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+#include <stdio.h>
+
+/*
+Exercise 2-4. Write an alternate version of squeeze (s 1,s2) that deletes
+each character in s1 that matches any character in the string s2.
+*/
+
+/*
+//squeeze: delete all c from s (needs below lines to work....)
+void squeeze(char s[], char c)
+{
+int i, j;
+
+for (i = j = 0; s[i] != '\0'; ++i)
+	{
+	if (s[i] != c)
+		{
+		s[j++] = s[i];
+		}
+	s[j] = '\0';
+	}
+}
+//int i;
+//strip null chars that are just there in the middle of the string... otherwise printf does not work
+//for (i=0;i<5;++i)
+//{
+//if (input[i] == '\0'){input[i] = input[i+1]; input[i+1] = '\0'; }
+//}
+
+*/
+
+
+//squeeze: Actual working reimplementation
+void squeeze(char s[], char c)
+{
+int i,j;
+for (i=0; s[i] != '\0'; ++i)
+	{
+	if (s[i] == c)//if s[i] is a charater to remove....
+		{
+		j=i;
+		while(s[j] != '\0'){s[j++] = s[j+1];}//shift all characters above left, overwriting the character
+		--i;//deincrement i, since the string was just shrunk by one and the one just above could indeed be a matching char
+		}
+	}
+}
+
+//squeezy: Delete all chars in s0 that match each single char in s1
+void squeezy(char s0[], char s1[])
+{
+int i,j,z;
+for (i=0; s0[i] != '\0'; ++i)
+	{
+	for (z=0; s1[z] != '\0'; ++z)
+		{
+		if (s0[i] == s1[z])//if s0[i] is a charater to remove....
+			{
+			j=i;
+			while(s0[j] != '\0'){s0[j++] = s0[j+1];}//shift all characters above left, overwriting the character
+			--i;//deincrement i, since the string was just shrunk by one and the one just above could indeed be a matching char
+			}
+		}
+	}
+}
+
+
+int main(void)
+{
+//note: "char *" cannot be modified like; s[0] = 'a', char s[] needs to be used instead
+char input[] = "Test input";
+
+//squeeze(input,'e');
+squeezy(input,"t");
+
+printf("%s\n", input);
+
+
+return 0;
+}
+